X^2-23x+16(2x)=0

Solution for X^2-23x+16(2x)=0 equation:

X^2-23X+16(2X)=0

We add all the numbers together, and all the variables

X^2+139X=0

a = 1; b = 139; c = 0;
Δ = b2-4ac
Δ = 1392-4·1·0
Δ = 19321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19321}=139$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(139)-139}{2*1}=\frac{-278}{2}
=-139
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(139)+139}{2*1}=\frac{0}{2}
=0
$